CCommons

Why 2S/r for a drop but 4S/r for a soap bubble, and which way does mercury go in a capillary?

Diya Menon11th Sample

1 Sept 2026 · 1 min read

omg I love this chapter and I hate it. 😭

Excess pressure inside a liquid drop is 2Sr\dfrac{2S}{r} and inside a soap bubble it's 4Sr\dfrac{4S}{r}. Our teacher says the soap bubble has "two surfaces". But my brain says a bubble is like a balloon, one skin. How is a soap film two surfaces? And an air bubble inside water, is it 2S/r or 4S/r?

Then capillary rise: h=2Scos⁡θrρgh = \dfrac{2S\cos\theta}{r\rho g}. I get that water climbs up the glass tube, but mercury goes down. The formula can do that, but I can't see how. What's the sign of the contact angle for mercury? And if I use a thicker tube for water, does it climb higher? (my guess: yes, more room to climb, like a wider staircase 😅)

Last: two soap bubbles of different radii connected by a tube. Which one grows? I would say the bigger one pushes into the smaller, since bigger = more air.

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  • [+]Meera Patel11thSample· 1mo ago

    A soap bubble is a thin film of liquid with air inside and air outside, so it has two liquid–air surfaces, the outer one and the inner one. Each surface adds an excess pressure of 2S/r2S/r (radius almost the same), so the total is 4S/r4S/r.

    Why a drop has 2S/r2S/r: with one surface. Derivation: if the radius increases by drdr, the work done by the excess pressure is ΔP⋅4πr2 dr\Delta P \cdot 4\pi r^2\,dr, and this equals the increase of surface energy S×8πr drS\times 8\pi r\,dr. So ΔP=2S/r\Delta P = 2S/r. For a bubble, the area has two surfaces, so you multiply by 2 and get 4S/r4S/r. An air bubble inside a liquid has just one surface, so 2S/r2S/r.

    • [+]Diya Menon11thSample· 1mo agoAuthor

      ahhh two surfaces = inner and outer skin of the film. like a samosa wrapper that's very thin but still has two faces 😂 thanks Meera!

  • [+]Yash Tiwari11thSample· 1mo ago

    bhai wetting ka scene hai. Contact angle chhota (acute) ho to liquid glass ko geela karta hai aur upar chadhta hai, jaise paani. Contact angle bada (obtuse) ho to liquid glass ko geela nahi karta, neeche jaata hai, jaise mercury. Real life examples: tel lamp ki batti mein upar chadhta hai, blotting paper se syahi chus leta hai, aur ped ke jad se paani upar jaata hai, capillarity ki wajah se (kuch had tak).

  • [+]Kavya NaikDropperSample· 1mo ago

    Diya, your staircase guess is the opposite of what happens. The formula says h∝1/rh \propto 1/r. Thinner tube, higher rise. Surface tension acts around the circumference (2πr2\pi r) to pull the liquid up, and what it has to lift is the column of weight πr2hρg\pi r^2 h\rho g. The pull goes with rr, the weight with r2r^2, so a wider tube has comparatively too much liquid to lift.

    For mercury, it isn't just the density. The contact angle between mercury and glass is obtuse (roughly 140°), so cos⁡θ\cos\theta is negative and hh comes out negative: mercury is depressed, with a convex meniscus. Water on clean glass has θ\theta close to 0°, so cos⁡θ≈1\cos\theta \approx 1 and the meniscus is concave.

    • [+]Diya Menon11thSample· 1mo agoAuthor

      wait so thin tube = higher rise, my staircase idea was totally backwards 😂 thanks Kavya didi

  • [+]Aman YadavDropperSample· 1mo ago

    Bubbles joined by a tube. Excess pressure is 4S/r4S/r, so the smaller bubble has the higher pressure. Air flows from the smaller to the larger one. The small one shrinks further, the large one grows. Counter-intuitive, I know, it's a standard MCQ trap.

    Different from a balloon, where the rubber gets stiffer as it stretches. A soap film's surface tension is constant, it doesn't depend on the area.

  • [+]Ishita GoyalDropperSample· 1mo ago

    A quick numerical for feel. Soap bubble, r=1r = 1 cm, S=0.03S = 0.03 N/m: ΔP=4S/r=4×0.03/0.01=12\Delta P = 4S/r = 4\times0.03/0.01 = 12 Pa. Tiny.

    Water in a tube of radius 0.5 mm, S=0.073S = 0.073 N/m, θ≈0\theta \approx 0:

    h=2Scos⁡θrρg=2×0.0730.5×10−3×1000×9.8≈0.03 m=3 cmh = \frac{2S\cos\theta}{r\rho g} = \frac{2\times0.073}{0.5\times10^{-3}\times1000\times9.8} \approx 0.03\ \text{m} = 3\ \text{cm}

    It's why the narrow capillaries in plants can pull water up a bit, while a normal glass doesn't climb anywhere.

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