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Why does thermodynamics feel like two different subjects in Physics and Chemistry?

Same first law, different sign conventions, different kinds of questions. Where do the Physics and Chemistry versions overlap, and where do they split?

Commons Community Team

17 Sept 2026 · 1 min read

This one comes up every week, usually right after a student loses marks on a sign. Thermodynamics shows up in Physics (heat engines, P-V graphs, specific heats, kinetic theory) and again in Chemistry (enthalpy, entropy, Gibbs energy), and the two books seem to speak different dialects. In Physics the first law is usually written Q=ΔU+WQ = \Delta U + W; in Chemistry it is ΔU=q+w\Delta U = q + w. Kinetic theory adds a third layer with degrees of freedom and 32kT\frac{3}{2}kT.

What makes it hard is not the maths. It is switching between chapters without noticing that the sign of work has quietly flipped. Plenty of you are doing every step right and still ending up with the opposite answer.

How do you keep the two versions apart? Share what has worked, especially if you met the Physics version first and the Chemistry one later, or the other way round.

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  • [+]Commons Physics DeskTeam· 1mo ago

    Think of Physics thermodynamics as a machine story: a gas in a cylinder does work on a piston, takes in heat, and you keep a ledger of the energy. Chemistry thermodynamics is a reaction story: what does a reaction do to energy and disorder? Same law, different cast.

    Kinetic theory is the bridge, because it tells you what internal energy is for an ideal gas: the motion energy of the molecules.

    IdeaResult
    Average KE per molecule32kT\frac{3}{2}kT
    Internal energy, nn moles, ff degrees of freedomU=f2nRTU = \frac{f}{2}nRT
    Molar heat capacitiesCV=f2RC_V = \frac{f}{2}R,   CP=CV+R\;C_P = C_V + R
    Ratioγ=1+2f\gamma = 1 + \frac{2}{f}

    Monatomic gas: f=3f = 3. Diatomic gas at ordinary temperatures (vibration not active): f=5f = 5. For an ideal gas, UU depends only on temperature, so in an isothermal process ΔU=0\Delta U = 0 and Q=WQ = W.

    Learn them in this order: kinetic theory, then the first law, then the four processes (isothermal, isobaric, isochoric, adiabatic). In the adiabatic case Q=0Q = 0 and PVγ=constantPV^{\gamma} = \text{constant}, so the work done by the gas comes entirely out of its internal energy, which is why an expanding gas cools.

  • [+]Commons Chemistry DeskTeam· 1mo ago

    The trap is the sign of work, and it is a trap because both conventions are legitimate.

    • Physics: WW is work done by the gas. Expansion gives positive WW. First law: Q=ΔU+WQ = \Delta U + W.
    • Chemistry (current NCERT/IUPAC style): ww is work done on the system. Expansion gives negative ww. First law: ΔU=q+w\Delta U = q + w.

    Take the same ideal gas expanding isothermally and reversibly. ΔU=0\Delta U = 0. Physics: Q=WQ = W, both positive. Chemistry: q=−wq = -w, with qq positive and ww negative. One physical event, two sign sets.

    A habit that saves marks: before touching a number, write the convention in the margin ("work BY gas" or "work ON system"), based on the subject the question sits in and the wording it uses.

    Then the Chemistry-only layer. Enthalpy is H=U+pVH = U + pV, so at constant pressure ΔH=qp\Delta H = q_p, and for reactions involving gases ΔH=ΔU+ΔngRT\Delta H = \Delta U + \Delta n_g RT. On top of that comes entropy and

    ΔG=ΔH−TΔS\Delta G = \Delta H - T\Delta S

    where the sign of ΔG\Delta G decides spontaneity at a given temperature. Physics seldom asks for ΔG\Delta G; Chemistry chapters seldom build engine cycles. That is the real split.

    • [+]Commons Physics DeskTeam· 1mo ago

      One link worth making: at constant pressure, the Physics heat Q=nCPΔTQ = nC_P\Delta T is the very quantity Chemistry calls ΔH\Delta H (when only pressure-volume work is involved). So the heat-capacity table above and the enthalpy chapter describe the same energy with different names.

  • [+]Commons Mock & PYQ DeskTeam· 1mo ago

    Two question styles keep appearing in mocks, and they punish different habits.

    Quick conceptual or ratio questions. "Ratio of rms speeds of two gases at the same temperature" is a classic. From vrms=3RT/Mv_{rms} = \sqrt{3RT/M}, the lighter gas is faster and v1/v2=M2/M1v_1/v_2 = \sqrt{M_2/M_1}. "γ\gamma for a diatomic gas" is the same type: if the table above is in your head, these take seconds.

    P-V graph questions. Area under the curve is work done by the gas. A closed loop's area is the net work. Clockwise loops on a P-V diagram mean net work is done by the gas (engine-like); anticlockwise means work is done on it. A common slip is to read the graph before identifying which process each segment is.

    For mock analysis, give each thermodynamics mistake one of three labels: sign, formula, or graph reading. After ten or so mistakes one label usually dominates, and then you know exactly what to revise instead of re-reading the whole chapter.

  • [+]Commons Strategy DeskTeam· 1mo ago

    Do not study the two versions as separate islands. An order many students settle on:

    1. Kinetic theory of gases first, since it explains what internal energy is.
    2. Physics thermodynamics: first law, the four processes, and the second law with reversible and irreversible processes. (The Carnot engine has been dropped from the rationalised NCERT text, so check the syllabus notice before spending time on it.)
    3. Some weeks later, Chemistry thermodynamics, with a one-page translation sheet next to your notes: sign of work, UU versus HH, and what ΔG\Delta G means.

    The translation sheet is two columns, Physics and Chemistry, describing the same events with matching signs. Rewrite it from memory once a week for a month. It takes about five minutes and it is the cheapest insurance against the sign flip.

    One caveat: topic lists get revised. Check the current NTA syllabus notice to see exactly what is in scope for each subject before you spend a week on a sub-topic.

    If you have your own trick for keeping the two sign conventions apart, post it below. Someone reading this thread tonight is hunting for exactly that.

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